vhdl_parser: ignore 'use work.all'

d6694bf2 · Tristan Gingold · c0a0320a · d6694bf2
Commit d6694bf2 authored Mar 30, 2020 by Tristan Gingold
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Showing with 4 additions and 1 deletion

vhdl_parser.py hdlmake/sourcefiles/vhdl_parser.py +4 -1

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--- a/hdlmake/sourcefiles/vhdl_parser.py
+++ b/hdlmake/sourcefiles/vhdl_parser.py
@@ -68,6 +68,9 @@ class VHDLParser(DepParser):
            file"""
            lib_name = text.group(1).lower()
            pkg_name = text.group(2).lower()
+            if pkg_name == "all":
+                # Forget 'use work.all'
+                return "";
            if lib_name == "work":
                # Work is an alias for the current library
                lib_name = dep_file.library
@@ -76,7 +79,7 @@ class VHDLParser(DepParser):
                DepRelation(pkg_name, lib_name, DepRelation.PACKAGE))
            return "<hdlmake use_pattern %s.%s>" % (lib_name, pkg_name)
        buf = re.sub(use_pattern, do_use, buf)
-        
+
        use_context_pattern = re.compile(
            r"^\s*context\s+(\w+)\s*\.\s*(\w+)\s*;",
            re.DOTALL | re.MULTILINE | re.IGNORECASE)